temos umas bhaskára, então temos:
a= 1
b= -7
c= 10
[tex]x^{2} -7x +10=0[/tex]
[tex]x= \frac{-(b) +- \sqrt{ (b)^{2} -4.a.c } }{2}[/tex]
[tex]x= \frac{-(-7) +- \sqrt{ (-7)^{2} -4.(1).(10) } }{2}[/tex]
[tex]x= \frac{7 +- \sqrt{ 49 -40 } }{2}[/tex]
[tex]x= \frac{7 +- \sqrt{ 9 } }{2}[/tex]
[tex]x= \frac{7 +- \sqrt{ 9 } }{2}[/tex]
[tex]x= \frac{7 +- 3 }{2}[/tex]
[tex]x'= \frac{7 + 3 }{2} = \frac{10}{2} = 5[/tex]
[tex]x"= \frac{7 - 3 }{2} = \frac{4}{2} = 2[/tex]
[tex] \left \{ {{x'=5} \atop {x"=2}} \right. [/tex]
