a) [tex]9^x<1=9^0\ portanto x<0[/tex]
b) [tex]5^x < 125=5^3\ portanto\ x<3[/tex]
c) Descreva melhor esta
d) [tex] 3^{x^2}>3^{11}\ portanto\ x^2<11\ portanto S=] -\infty, -\sqrt{11}[U]\sqrt{11},\infty[ [/tex]
e) [tex]a^{x^2}>a^{-6x^{-5}}\ portanto\ x^2>-6x^{-5}= \frac{-6}{x^{5}} \ portanto\ x^7>-6[/tex]
[tex]x> -\sqrt[7]{6} [/tex]
f) [tex] (\frac{1}{4}) ^x \geq 1/64\ portanto\ 2^{-2x} \geq 2^{-6}\ portanto\ -2x \geq -6 [/tex]
[tex]x \leq 6/2\ portanto\ x<3[/tex]
g) [tex] (\frac{1}{7})^{2x^{-1}}<1= (\frac{1}{7})^0\ portanto\ \frac{2}{x}<0\ portanto\ x<0 [/tex]
Hugs
