[tex]\large\boxed{\begin{array}{l} n + n + 1 + n + 2 = 339 \\ \\ 3n + 3 = 339 \\ \\ 3n = 339 - 3 \\ \\ 3n = 336 \\ \\ n = \dfrac{336}{3} \\ \\ \boxed{n=112 \: \: (1)} \\ \\ n = 112 + 1 \\ \\ \boxed{n = 113 \: \: (2)} \\ \\ n = 113 + 1 \\ \\ \boxed{n = 114 \: \: (3)} \\ \\ \rm{depois \: dos \: c\acute{a}lculos\, conclu\acute{i}mos\, que\, }\\ \rm{os\, tr\hat{e}s\, n\acute{u}meros\, s\tilde{a}o : } \\ \\ \red{\Large\boxed{\begin{array}{l} \Large\boxed{\begin{array}{l} \rm{\therefore \: 112,113 \: e \: 114 \: }\end{array}}\end{array}}}\end{array}}[/tex]
