[tex]\sf tan \left(\pi -x\right)=\dfrac{tan \left(\pi \right)-tan \left(x\right)}{1+tan \left(\ \pi \right)tan \left(x\right)}\\\\\\{Manipule\:o\:lado\:direito}\\\\\\tan \left(\pi -x\right)\\\\\\=-\dfrac{sin \left(x\right)}{cos \left(x\right)}\\\\\\{Manipule\:o\:lado\:esquerdo}\\\\\\\dfrac{tan \left(\pi \right)-tan \left(x\right)}{1+tan \left(\pi \right)tan \left(x\right)}\\\\\\Expresse \ com \ Seno , cosseno\\\\\\=-\dfrac{sin \left(x\right)}{cos \left(x\right)}\\\\\\[/tex]
[tex]\sf {Então \: Podemos \: Afirmar \:que\:os\:dois\:lados\:podem\:adquirir\:a\:mesma\:forma}\\\\\\ \boxed{\sf \Rightarrow {Verdadeiro}}[/tex]
