Resposta:
Alternativa 4)
Explicação passo-a-passo:
[tex]\displaystyle A+B=\left[\begin{array}{ccc}x-2&1\\y&z\end{array}\right]+ \left[\begin{array}{ccc}3&2\\2z&x\end{array}\right] =\left[\begin{array}{ccc}x-2+3&1+2\\y+2z&z+x\end{array}\right] =\left[\begin{array}{ccc}x+1&3\\y+2z&z+x\end{array}\right] =\left[\begin{array}{ccc}3&3\\0&0\end{array}\right][/tex]
x+1=3 => x=3-1=2
z+x=0 => z= -x= -2
y+2z=0 => y= -2z= -2(-2)= 4
(x+y)/z=(2+4)/(-2)= -6/2= -3
