Resposta:
Explicação passo a passo:
[tex]a^{0}=1\;se\:a\neq 0[/tex]
[tex]a^{m}\:.\:a^{n} =a^{(m+n)}[/tex]
[tex]a^{m}:a^{n}=a^{(m-n)}[/tex]
[tex](a^{m})^{n} =a^{m.n}[/tex]
[tex]a^{-m} =\frac{1}{a^{m} }[/tex]
[tex](\frac{a}{b}) ^{-m} =(\frac{b}{a}) ^{m}[/tex]
[tex]a)[/tex]
[tex](7^{8})^{8}=7^{64}[/tex]
[tex]b)[/tex]
[tex](7^{4})^{3}=7^{12}[/tex]
[tex]c)[/tex]
[tex]12^{0}=1[/tex]
[tex]d)[/tex]
[tex]13^{-2}=\frac{1}{(13)^{2} } =\frac{1}{169}[/tex]
[tex]e)[/tex]
[tex](\frac{5}{7}) ^{-5} =(\frac{7}{5}) ^{5}[/tex]
[tex]f)[/tex]
[tex](6^{2})^{7}=6^{14}[/tex]
[tex]g)[/tex]
[tex](\frac{3^{11} }{3^{4} }) ^{2} =(3^{7})^{2} =3^{14}[/tex]
