Resposta:
[tex]\textsf{Leia abaixo}[/tex]
Explicação passo a passo:
[tex]\mathsf{10x^2 + 8x + 1 = 0}[/tex]
[tex]\mathsf{\Delta = b^2 - 4.a.c}[/tex]
[tex]\mathsf{\Delta = 8^2 - 4.10.1}[/tex]
[tex]\mathsf{\Delta = 64 - 40}[/tex]
[tex]\mathsf{\Delta = 24}[/tex]
[tex]\mathsf{x = \dfrac{-b \pm \sqrt{\Delta}}{2a} = \dfrac{-8 \pm \sqrt{24}}{20} \rightarrow \begin{cases}\mathsf{x' = \dfrac{-8 + 2\sqrt{6}}{20} = \dfrac{-4 + \sqrt{6}}{10}}\\\\\mathsf{x'' = \dfrac{-8 - 2\sqrt{6}}{20} = \dfrac{-4 - \sqrt{6}}{10}}\end{cases}}[/tex]
[tex]\mathsf{S = \left\{\dfrac{-4 + \sqrt{6}}{10}};\dfrac{-4 - \sqrt{6}}{10}}\right\}}[/tex]
