Resposta:
[tex]3x ^ { 2 } -2x+1=0 \\ x=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}-4\times 3}}{2\times 3} \\ x=\frac{-\left(-2\right)±\sqrt{4-4\times 3}}{2\times 3} \\ x=\frac{-\left(-2\right)±\sqrt{4-12}}{2\times 3} \\ x=\frac{-\left(-2\right)±\sqrt{-8}}{2\times 3} \\ x=\frac{-\left(-2\right)±2\sqrt{2}i}{2\times 3} \\ x=\frac{2±2\sqrt{2}i}{2\times 3} \\ x=\frac{2+2\sqrt{2}i}{6} \\ x=\frac{1+\sqrt{2}i}{3} \\ x=\frac{-2\sqrt{2}i+2}{6} \\ x=\frac{-\sqrt{2}i+1}{3} \\ x=\frac{1+\sqrt{2}i}{3} \\ x=\frac{-\sqrt{2}i+1}{3}[/tex]
