[tex]\boxed{\boxed{\bf{\red{Olá}}}}[/tex]
Bhaskara
Vamos a os cálculos...
[tex] \boxed{x² - 6x + 8 = 0}[/tex]
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[tex]a = 1 \\ b = - 6 \\ c = 8 \\ \\ ∆ = b {}^{2} - 4.a.c \\ ∆ = ( - 6) {}^{2} - 4.1.8 \\ ∆ = 36 - 32 \\ ∆ = 4 \\ \\ x = \frac{- b± \sqrt{∆} }{2.a} \\ \\ x = \frac{ - ( - 6)± \sqrt{4} }{2.1} \\ \\ x = \frac{6±2}{2} \\ \\ x1 = \frac{6 + 2 }{2} \\ \\ x1 = \frac{8}{2} \\ \\ \boxed{x1 = 4} \\ \\ x2 = \frac{6 - 2}{2} \\ \\ x2 = \frac{4}{2} \\ \\ \boxed{x2 = 2} \\ \\ \boxed{s = {[4,2]}}[/tex]
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Resposta ☞︎︎︎ B) 2 e 4
