Resposta:
Explicação passo a passo:
a) [tex]\sqrt[10]{2^{4}}=2^\frac{4}{10}=2^\frac{2}{5}=\sqrt[5]{2^{2}}[/tex]
b)[tex]\sqrt{27}=\sqrt{3^{3}}=\sqrt{3^{2}\cdot 3}= 3\sqrt{3}[/tex]
c)[tex]\sqrt{3^{8}}=3^\frac{8}{2}=3^4=81[/tex]
d)[tex]\sqrt[3]{x^3}=x^\frac{3}{3}=x[/tex]
e)[tex]\sqrt{9^{2}}=9^\frac{2}{2}=9[/tex]
f)[tex]\sqrt{(a-b)^{2}}=(a-b)^\frac{2}{2}=a-b[/tex]
