[tex]\Large\boxed{\begin{array}{l}\underline{\rm Equac_{\!\!,}\tilde ao\,balanceada}\\\sf FeCl_2+H_2SO_4\longrightarrow FeSO_4+2HCl\\\sf 6\cdot10^{23}\,mol\acute eculas\,de\,FeCl_2\longrightarrow22,4\,L\,de\,H_2SO_4\\\sf x\longrightarrow 44,8\\\sf 22,4x=44,8\cdot6\cdot10^{23}\\\sf x=\dfrac{\diagdown\!\!\!\!\!\!44,\backslash\!\!\!8\cdot6\cdot10^{23}}{\diagdown\!\!\!\!\!\!22,\backslash\!\!\!4}\\\\\sf x=2\cdot6\cdot10^{23}\\\sf x=12\cdot10^{23}\\\sf x=1,2\cdot10^{24}\,mol\acute eculas\end{array}}[/tex]
[tex]\Large\boxed{\begin{array}{l}\bf Para\,uma\,melhor\,visualizac_{\!\!,}\tilde ao\\\bf observe\,a\,figura\,anexa.\end{array}}[/tex]
