[tex] > resolucao \\ \\ \geqslant progressao \: aritmetica \\ \\ \geqslant \: o \: 5 \: termo \: da \: pa \\ \\ a10 = a1 + 9r \\ 5 = 2 + 9r \\ 5 - 2 = 9r \\ 3 = 9r \\ r = \frac{3 \div 3}{9 \div 3} \\ r = \frac{1}{3} \\ \\ \\ an = a1 + (n - 1)r \\ an = 2 + (5 - 1) \frac{1}{3} \\ an = 2 + 4 \times \frac{1}{3} \\ an = 2 + \frac{4}{3} \\ an = \frac{6 + 4}{3} \\ an = \frac{10}{3} \\ \\ > < > < > < > < > < > < > < > > [/tex]
