2006324idn
Answered

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PERGUNTA 5

Considere a seguinte relação no conjunto S equals left curly bracket 1 comma 2 comma 3 comma 4 comma 5 right curly bracket.
rho equals left curly bracket left parenthesis 1 comma 1 right parenthesis comma left parenthesis 1 comma 2 right parenthesis comma left parenthesis 3 comma 3 right parenthesis comma left parenthesis 2 comma 1 right parenthesis comma left parenthesis 4 comma 2 right parenthesis right curly bracket.
Assinale a alternativa que corresponde ao fecho rho to the power of asterisk times da relação rho, com respeito à simetria.

a.
rho to the power of asterisk times equals left curly bracket left parenthesis 1 comma 1 right parenthesis comma left parenthesis 1 comma 2 right parenthesis comma left parenthesis 3 comma 3 right parenthesis comma left parenthesis 2 comma 1 right parenthesis comma left parenthesis 4 comma 2 right parenthesis right curly bracket.

b.
rho to the power of asterisk times equals left curly bracket left parenthesis 1 comma 1 right parenthesis comma left parenthesis 1 comma 2 right parenthesis comma left parenthesis 3 comma 3 right parenthesis comma left parenthesis 2 comma 1 right parenthesis comma left parenthesis 4 comma 2 right parenthesis comma left parenthesis 2 comma 2 right parenthesis comma left parenthesis 4 comma 4 right parenthesis comma left parenthesis 5 comma 5 right parenthesis right curly bracket.

c.
rho to the power of asterisk times equals left curly bracket left parenthesis 1 comma 1 right parenthesis comma left parenthesis 1 comma 2 right parenthesis comma left parenthesis 3 comma 3 right parenthesis comma left parenthesis 2 comma 1 right parenthesis comma left parenthesis 4 comma 2 right parenthesis comma left parenthesis 2 comma 4 right parenthesis right curly bracket.

d.
rho to the power of asterisk times equals left curly bracket left parenthesis 1 comma 1 right parenthesis comma left parenthesis 1 comma 2 right parenthesis comma left parenthesis 3 comma 3 right parenthesis comma left parenthesis 2 comma 1 right parenthesis comma left parenthesis 4 comma 2 right parenthesis comma left parenthesis 5 comma 5 right parenthesis right curly bracket.

e.
rho to the power of asterisk times equals left curly bracket left parenthesis 1 comma 1 right parenthesis comma left parenthesis 1 comma 2 right parenthesis comma left parenthesis 3 comma 3 right parenthesis comma left parenthesis 2 comma 1 right parenthesis comma left parenthesis 4 comma 2 right parenthesis comma left parenthesis 3 comma 1 right parenthesis comma left parenthesis 1 comma 3 right parenthesis right curly bracket.

Sagot :

Resposta:

{(1,1), (1,2),(3,3),(2,1),(4,2),(2,4)}

Explicação passo a passo:

conferido no ava

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