[tex]x = \frac{526}{495} + [\frac{((-2)^{2\sqrt2 - 1})^{2\sqrt2 + 1}}{128}]^{-1} \\\\ x = \frac{526}{495} + [\frac{128}{((-2)^{2\sqrt2 - 1})^{2\sqrt2 + 1}}] \\\\ x = \frac{526}{495} + [\frac{128}{(-2)^{8 - 1}}] \\\\ x = \frac{526}{495} + [\frac{128}{(-2)^{7}}] \\\\ x = \frac{526}{495} + [\frac{128}{-128}] \\\\ x = \frac{526}{495} + (-1) \\\\ x = \frac{526}{495} - \frac{495}{495} \\\\ x = \frac{31}{495}[/tex]
[tex]\bullet \ \text{Se} \ x = \frac{31}{495} \\\\ -x \ \text{(oposto)} = -\frac{31}{495} = - 0,0626262... \approx -0,0626[/tex]
O número -0,0626 está compreendido entre -0,63 e -0,62, portanto, opção c.
