Os gráficos estão em anexo.
a)
[tex]\boxed{f(x)=x^2}[/tex]
[tex]x=-3\ \to\ f(-3)=(-3)^2=9\ \to\ \boxed{A(-3,9)\in f(x)}[/tex]
[tex]x=-2\ \to\ f(-2)=(-2)^2=4\ \to\ \boxed{B(-2,4)\in f(x)}[/tex]
[tex]x=-1\ \to\ f(-1)=(-1)^2=1\ \to\ \boxed{C(-1,1)\in f(x)}[/tex]
[tex]x=0\ \to\ f(0)=(0)^2=0\ \to\ \boxed{D(0,0)\in f(x)}[/tex]
[tex]x=1\ \to\ f(1)=(1)^2=1\ \to\ \boxed{E(1,1)\in f(x)}[/tex]
[tex]x=2\ \to\ f(2)=(2)^2=4\ \to\ \boxed{F(2,4)\in f(x)}[/tex]
[tex]x=3\ \to\ f(3)=(3)^2=9\ \to\ \boxed{G(3,9)\in f(x)}[/tex]
b)
[tex]\boxed{f(x)=x^2+2}[/tex]
[tex]x=-2\ \to\ f(-2)=(-2)^2+2=6\ \to\ \boxed{A(-2,6)\in f(x)}[/tex]
[tex]x=-1\ \to\ f(-1)=(-1)^2+2=3\ \to\ \boxed{B(-1,3)\in f(x)}[/tex]
[tex]x=0\ \to\ f(0)=(0)^2+2=2\ \to\ \boxed{C(0,2)\in f(x)}[/tex]
[tex]x=1\ \to\ f(1)=(1)^2+2=3\ \to\ \boxed{D(1,3)\in f(x)}[/tex]
[tex]x=2\ \to\ f(2)=(2)^2+2=6\ \to\ \boxed{E(2,6)\in f(x)}[/tex]
c)
[tex]\boxed{f(x)=-2x^2+4x}[/tex]
[tex]x=-1\ \to\ f(-1)=-2(-1)^2+4(-1)=-6\ \to\ \boxed{A(-1,-6)\in f(x)}[/tex]
[tex]x=0\ \to\ f(0)=-2(0)^2+4(0)=0\ \to\ \boxed{B(0,0) \in f(x)}[/tex]
[tex]x=1\ \to\ f(1)=-2(1)^2+4(1)=2\ \to\ \boxed{C(1,2)\in f(x)}[/tex]
[tex]x=2\ \to\ f(2)=-2(2)^2+4(2)=0\ \to\ \boxed{D(2,0)\in f(x)}[/tex]
[tex]x=3\ \to\ f(3)=-2(3)^2+4(3)=-6\ \to\ \boxed{E(3,-6)\in f(x)}[/tex]
