[tex] > \:resolucao \\ \\ \geqslant \: progressao \: \: geometrica \\ \\ sn = 4092 \\ n = 10 \\ q = 2 \\ \\ = = = = = = = = = = = = = = = \\ \\ \\ > \: o \: primeiro \: termo \: da \: pg \\ \\ \\ sn = \frac{a1(q {}^{n} - 1)}{q - 1} \\ \\ 4092 = \frac{a1(2 {}^{10} - 1) }{2 - 1} \\ \\ 4092 = \frac{a1(1024 - 1)}{1} \\ \\ 4092 = a1(1023) \\ \\ a1 = \frac{4092}{1023} \\ \\ a1 = 4 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant [/tex]
