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A boy asked about his age replied square of my age minus her sextuple and equal to 16 years old equal to this boy's age the calculation is x²-6x=16

Sagot :

To solve the problem, we start with the equation given:

\[ x^2 - 6x = 16 \]

First, rearrange all terms to one side to form a quadratic equation:

\[ x^2 - 6x - 16 = 0 \]

Next, we will solve this quadratic equation using the quadratic formula, \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 1 \), \( b = -6 \), and \( c = -16 \).

Calculate the discriminant:

\[ b^2 - 4ac = (-6)^2 - 4 \cdot 1 \cdot (-16) \]

\[ = 36 + 64 \]

\[ = 100 \]

Now, find the square root of the discriminant:

\[ \sqrt{100} = 10 \]

Substitute back into the quadratic formula:

\[ x = \frac{-(-6) \pm 10}{2 \cdot 1} \]

\[ x = \frac{6 \pm 10}{2} \]

This gives us two possible solutions for \( x \):

\[ x = \frac{16}{2} = 8 \]

\[ x = \frac{-4}{2} = -2 \]

Since age cannot be negative, we discard \( x = -2 \).

Therefore, the boy's age is \( x = 8 \).

To verify, substitute \( x = 8 \) back into the original context of the problem:

- Square of the boy's age: \( 8^2 = 64 \)

- Six times the girl's age: \( 6 \cdot 8 = 48 \)

- The difference: \( 64 - 48 = 16 \)

The calculations match the conditions given in the problem statement. Thus, the boy's age is confirmed to be {8}