Resposta:
[tex]\textsf{Leia abaixo}[/tex]
Explicação passo a passo:
[tex]\begin{cases}\mathsf{tg\:30\textdegree = \dfrac{y}{x + 40}}\\\\\mathsf{tg\:60\textdegree = \dfrac{y}{x}}\end{cases}[/tex]
[tex]\begin{cases}\mathsf{\dfrac{\sqrt{3}}{3} = \dfrac{y}{x + 40}}\\\\\mathsf{\sqrt{3} = \dfrac{y}{x}}\end{cases}[/tex]
[tex]\mathsf{y = x\sqrt{3}}[/tex]
[tex]\mathsf{\dfrac{\sqrt{3}}{3} = \dfrac{x\sqrt{3}}{x + 40}}}[/tex]
[tex]\mathsf{\dfrac{1}{3} = \dfrac{x}{x + 40}}}[/tex]
[tex]\mathsf{3x = x + 40}[/tex]
[tex]\mathsf{2x = 40}[/tex]
[tex]\boxed{\boxed{\mathsf{x = 20}}}[/tex]
[tex]\boxed{\boxed{\mathsf{y = 20\sqrt{3}}}}[/tex]
